How much heat is released in 10 minutes in a 200 Ohm resistor connected to a 50 V network?

t = 10 min = 600 s.
R = 200 ohms.
U = 50 V.
Q -?
According to the Joule-Lenz law, the amount of heat in a conductor through which an electric current flows is determined by the formula: Q = U ^ 2 * t / R.
Q = (50 V) ^ 2 * 600 s / 200 Ohm = 7500 J.
Answer: Q = 7500 J of thermal energy will be released in the resistor.



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