How much heat is required for that; to steam 300 g of zinc at boiling point?

How much heat is required for that; to steam 300 g of zinc at boiling point? The specific heat of vaporization of zinc is 1.8 MJ / kg.

Initial data: m (mass of zinc to be converted into steam) = 300 g (0.3 kg); zinc is taken at boiling point (906.2 ºС).

Reference values: according to the condition L (specific heat of vaporization of zinc) = 1.8 MJ / kg (1.8 * 10 ^ 6 J / kg).

The amount of heat that will need to be spent on the conversion of zinc into steam is calculated by the formula: Q = L * m.

Let’s calculate: Q = 1.8 * 10 ^ 6 * 0.3 = 0.54 * 10 ^ 6 = 0.54 MJ.

Answer: You will need 0.54 MJ of heat.