How much heat is required if 2 kg of ice is placed in an aluminum pot weighing 300 g

How much heat is required if 2 kg of ice is placed in an aluminum pot weighing 300 g. , melt on a fire with an efficiency of 5% and evaporate 20 g of water.

Data: m1 (ice) = 2 kg; m3 (aluminum pot) = 300 g (0.3 kg); m2 (evaporated water) = 20 g (0.02 kg); η (efficiency) = 5% (0.05); tн = 0 ºС.

Reference data: tm = 0 ºС; λ = 3.4 * 10 ^ 5 J / kg; C1 (water) = 4200 J / (kg * ºС); С3 (aluminum pot) = 920 J / (kg * ºС); tк = 100 ºС; L = 2.3 * 10 ^ 6 J / kg.

η = Qp / Qz and Qz = Qp / η = (λ * m1 + C1 * m1 * (tk – tn) + L * m2 + C3 * m3 * (tk – tn)) / η = (3.4 * 10 ^ 5 * 2 + 4200 * 2 * (100 – 0) + 2.3 * 10 ^ 6 * 0.02 + 920 * 0.3 * (100 – 0)) / 0.05 = 31,872,000 J.