How much heat is required to boil 2 kg of water in an aluminum kettle weighing 700 g?

How much heat is required to boil 2 kg of water in an aluminum kettle weighing 700 g? Initial water temperature 20 C.

m1 = 700 g = 0.7 kg – mass of aluminum
m2 = 2 kg – mass of water
t1 = 20 C
t2 = 100 С – boiling point of water
C1 = 920 J / kg * s – specific heat capacity of aluminum
С2 = 4200 J / kg * С – specific heat of water
Q -?
Q1 = C1 * m1 * (t2-t1) – the amount of heat required to heat aluminum
Q2 = C2 * m2 * (t2-t1) – the amount of heat required to heat water
Q = Q1 + Q2 – total amount of heat
Q1 = 920 * 0.7 * (100-20) = 51520 J
Q2 = 4200 * 2 * (100 – 20) = 672000 J
Q = 672000 + 51520 = 723520 J