How much heat is required to convert 3 kg of ice taken at a temperature of -20C into steam at a temperature of 100C?

Q = Q1 + Q2 = cmΔt + Lm
Δt – temperature difference (0 С – (- 20 С) = 0 + 20 = 20 С)
Q = 2100 * 3 * 20 + 2256000 * 3 = 126000 + 6768000 = 6894000 J = 6.894 mJ



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