How much heat is required to convert water weighing 2 kg, taken at a temperature of 35 degrees, into steam?

univerkov | July 17, 2021 | education

Given: m (mass of water to be converted into steam) = 2 kg; t (temperature of taken water) = 35 ºС.

Reference data: Cw (specific heat) = 4200 J / (kg * ºС); tpap (vaporization temperature) = 100 ºС; L (specific heat of vaporization) = 23 * 10 ^ 5 J / kg.

1) Heating: Q1 = Cw * m * (tp – t) = 4200 * 2 * (100 – 35) = 4200 * 2 * 65 = 546000 J = 546 kJ.

2) Conversion to steam: Q2 = L * m = 23 * 10 ^ 5 * 2 = 46 * 10 ^ 5 J = 4600 kJ.

3) Required amount of heat: Q = Q1 + Q2 = 546 + 4600 = 5146 kJ.

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