How much heat is required to evaporate 4 kg of water at a temperature of 100 C?

The amount of energy required for water vaporization is calculated using the formula:
Q = L * m, where L is the specific heat of vaporization of water (L = 2.3 * 10 ^ 6 J / kg), m is the mass of water (m = 4 kg).
Let’s calculate the required amount of energy for water vaporization:
Q = L * m = (2.3 * 10 ^ 6) * 4 = 9.2 * 10 ^ 6 J = 9.2 MJ.
Answer: D) 9.2 MJ of heat is required for water vaporization.



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