How much heat is required to heat 0.25 kg of water from 30 C to 50 C?
| September 28, 2021 | education
m = 0.25kg,
t1 = 30 ° С,
t2 = 50 ° С,
c = 4200J / (kg * deg);
Q -?
The amount of heat required to heat water:
Q = m * c * (t2 – t1) = 0.25 * 4200 * 20 = 21000J = 21kJ.
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