How much heat is required to heat 0.25 kg of water from 30 C to 50 C.
| November 23, 2020 | education
The amount of heat will be calculated by the formula Q = cm * (t2 – t1), t2 is the final body temperature, t1 is the initial one. c – specific heat, this is a tabular value. For water with = 4200 J / kg × ° С
Q = 4200 J / ° С × kg * 0.25 kg * (50-30 ° С) = 21,000 Joules or 21 kJ.
Answer: 21,000 J
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