How much heat is required to heat 1.5 liters of water from 20 degrees to 100 in an aluminum pot weighing 200 grams?
| July 7, 2021 | education
Q = Q1 + Q2.
Q1 (water heating) = C1 * m1 * (tк – tн); C1 – beats. heat capacity (C1 = 4200 J / (kg * K)), m1 is the mass of water (m1 = ρ * V; ρ (water density) = 1000 kg / m3, V (volume) = 1.5 l = 1.5 * 10-3 m3), tк = 100 ºС, tн = 20 ºС.
Q2 (boiler heating) = С2 * m2 * (tк – tн); C2 – beats. heat capacity (for aluminum C2 = 920 J / (kg * K)), m2 is the mass of the pot (m2 = 200 g = 0.2 kg).
Q = (C1 * ρ * V + C2 * m2) * (tk – tn) = (4200 * 1000 * 1.5 * 10-3 + 920 * 0.2) * (100 – 20) = 518720 J.
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