How much heat is required to heat 100 kg steel from 20 to 300 degrees?

univerkov | January 26, 2021 | education

Given:
m = 100 kg – weight of steel
t1 = 20 C
t2 = 300 C
c = 500 J / kg * С – specific heat capacity of steel
Q -?
We leave the SI column empty, since nothing needs to be translated
Decision:
Q = c * m * (t2-t1)
Q = 500 * 100 * (300-20) = 14,000,000 J = 14 MJ
Answer: Q = 14 MJ

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