How much heat is required to heat 15 kg of water from 20 to 80?
| December 11, 2020 | education
t = twenty C
m = Ten kilograms
c = 4200 J / kg * C
t1 = One hundred C
Q-?
Answer:
Q = cm (t1-t0)
Q = 4200 * 10 * (One Hundred-Twenty) = 3360000 J
Result: 3,360,000 J.
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