How much heat is required to heat 20g water by 8 degrees Celsius?

Given: m (mass of water to be heated) = 20 g (in SI m = 0.02 kg); Δt (temperature change during heating) = 8 ºС.

Constants: Cw (specific heat of water) = 4200 J / (kg * K).

The heat consumption for heating 20 g of water is calculated by the formula: Q = Sv * m * Δt.

Let’s calculate: Q = 4200 * 0.02 * 8 = 672 J.

Answer: To heat 20 g of water, 672 J of heat will be required.



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