How much heat is required to heat 250 g of water for 5 seconds?

The formula that we can apply in this case is Q = cm (t load – t start), where Q is the amount of heat required to heat the body, c is the specific heat capacity of the substance, m is the body weight, t load is the temperature up to which the body was heated, t start is the initial temperature at which the bodies began to be heated.

(t heat – t start) – temperature difference, that is, its value by which the body was heated, in our case – 5 ° C.

The specific heat capacity of water is 4183 J / kg ° С.

250 g of water means a mass of 0.25 kg (the density of water is 1000 kg / m3 or 1 kg / l).

Substituting the values ​​into the above formula, we get – Q = (4183 J / kg ° C) * (0.25 kg) * (5 ° C).

Answer: to heat water according to the given conditions of the problem, the amount of heat will be required – Q = 5228.75 J.