How much heat is required to heat a 0.5 kg piece of steel from 20 to 30 degrees C?

Given: m (mass of a given piece of steel) = 0.5 kg; t0 (initial temperature of the piece) = 20 ºС; t (required temperature) = 30 ºС.

Reference values: Сс (specific heat capacity of steel) = 500 J / (kg * K).

The heat consumption for heating a given piece of steel is calculated by the formula: Q = Cc * m * (t – t0).

Let’s calculate: Q = 500 * 0.5 * (30 – 20) = 2.5 * 10 ^ 3 J (2.5 kJ).

Answer: To heat a given piece of steel, 2.5 kJ of heat is required.

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