How much heat is required to heat a 400 g steel part from 15 ° C to 75 ° C?

Task data: m (weight of the steel part) = 400 g (0.4 kg); tн (initial temperature of the steel part) = 15 ºС; tк (final heating temperature of the part) = 75 ºС.
Constants: C (specific heat capacity of steel) = 500 J / (kg * ºС).
The amount of heat that will be spent to heat the steel part is calculated by the formula: Q = C * m * (tк – tн).
Let’s make the calculation: Q = 500 * 0.4 * (75 – 15) = 12000 J (12 kJ).
Answer: Heating a steel part requires 12 kJ of heat.