How much heat is required to increase the temperature of water weighing 100 grams by 1 degree.

Initial data:
The amount of heat – Q (?)
Weight – M (100g = 0.1kg)
Specific heat – C (this is a tabular value. For water – 4200 J / kg * ° s)
∆t ° = 1 °
Decision:
We use the formula Q = CxMx∆t
Q = 4200×0.1×1 ° = 420 J
Answer: Q = 420 J.



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