# How much heat is required to melt 240 g of tin if its initial temperature is 22 degrees C?

**How much heat is required to melt 240 g of tin if its initial temperature is 22 degrees C? The specific heat of tin is 230 J. kg * C, the specific heat of fusion of tin is 6 * 10 J. kg, and the melting point is 232 degrees C.**

Here are the data from given in SI:

m = 240 g = 0.24 kg.

t1 = 22 ° C = 22 + 273 = 295 K

t2 = 232 ° C = 232 + 273 = 505 K

1. The amount of heat spent on heating the body is equal to the product of the specific heat capacity of the substance, body weight and the difference between the final and initial temperatures.

Q = c * m * (t2-t1), where c is the specific heat capacity of the substance, m is the mass of the substance, t2 and t1 are the final and initial temperatures, respectively.

Substituting numerical data into the formula, we get:

Q1 = c * m * (t2-t1) = 230 * 0.24 * (505-295) = 11592 J

To heat tin to the melting temperature, 11592 J of heat must be spent.

2. To melt the tin, the required amount of heat:

Q = λ * m, where λ is the specific heat of fusion of the substance, m is the mass of the substance.

Substituting numerical data into the formula, we get:

Q2 = λ * m = 6 * 10 ^ 4 * 0.24 = 14400 J

3. Total amount of heat:

Q = Q1 + Q2 = 11592 + 14400 = 25992 J

Answer: to melt tin, you need 25992 J of heat, or 26 kJ.