How much heat is required to melt 240 g of tin, if its initial temperature is 220C?
| April 28, 2021 | education
How much heat is required to melt 240 g of tin, if its initial temperature is 220C? Specific heat of tin 230 J / kg * 0С, specific heat of fusion of tin 6 * 104 J / kg, melting point 2320С.
Required amount of heat: Q = Q1 + Q2.
Q1 (heating of tin) = C * m * (tmelt – tn); С – specific heat capacity (С = 230 J / (kg * K)), m – mass of tin (m = 240 g = 0.24 kg), tк – melting temperature (tmelt = 2320 ºС), tн – initial temperature (tн = 220 ºС).
Q2 (tin melting) = λ * m; λ – specific heat of fusion (λ = 6 * 10 ^ 4 J / kg).
Q = 230 * 0.24 * (2320 – 220) + 6 * 10 ^ 4 * 0.24 = 115920 + 14400 = 130320 J.
Answer: To melt 240 g of tin, 130 320 J of heat is required.
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