How much heat is required to melt 500 g of aluminum taken at a temperature of 20 s?
| September 25, 2021 | education
Q = Q1 + Q2.
Q1 = C * m * (tc – tn), where C is the specific heat capacity of aluminum (C = 920 J / (K * kg)), m is the mass of aluminum (m = 500 g = 0.5 kg), tc is the temperature melting (tк = 660 ºС), tн – initial temperature (tн = 20 ºС).
Q2 = λ * m, where λ is the specific heat of fusion (λ = 3.9 * 105 J / kg).
Q = Q1 + Q2 = C * m * (tc – tn) + λ * m = 920 * 0.5 * (660 – 20) + 3.9 * 105 * 0.5 = 294400 + 195000 = 489400 J = 489 , 4 kJ.
Answer: To melt aluminum, you need 489.4 kJ of heat.
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