How much heat is required to melt lead weighing 0.2 kg and having a temperature of 327 degrees?
| September 5, 2021 | education
Given:
m = 0.2 kilograms is the mass of lead;
q = 22.6 kJ / kg = 22600 J / kg is the specific heat of fusion of lead;
T = 327 degrees – the melting point of lead.
It is required to determine the amount of heat Q (Joule) required to melt the lead.
Since, according to the condition of the problem, lead is already at the melting temperature, then:
Q = q * m = 22600 * 0.2 = 4520 Joules.
Answer: to melt lead, you need to spend an energy equal to 4520 Joules.
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