How much heat is required to turn 50 grams of mercury into steam, taken at a temperature of 27 degrees?

| June 15, 2021 | education

How much heat is required to turn 50 grams of mercury into steam, taken at a temperature of 27 degrees? The boiling point of mercury is 357 degrees, the specific heat of mercury is 130 J / (kg * degrees), the specific heat of vaporization of water is 0.3 MJ / kg

Data: m (mass of mercury for transition to vapor) = 50 g (0.05 kg); t0 (initial temperature of mercury) = 27 ºС.

Constants: by condition tboil (boiling point) = 357 ºС; С (specific heat capacity of mercury) = 130 J / (kg * ºС); L (specific heat of vaporization) = 0.3 MJ / kg (0.3 * 10 ^ 6 J).

1) Heating mercury to boiling: Q1 = C * m * (tboil – t0) = 130 * 0.05 * (357 – 27) = 2145 J.

2) The transition of mercury to vapor: Q2 = L * m = 0.3 * 10 ^ 6 * 0.05 = 15000 J.

3) Required heat: Q = Q1 + Q2 = 15000 + 2145 = 17 145 J.



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