How much heat must be expended to melt an iron part weighing 2 kg, if its initial temperature is 39 degrees Celsius?

Data: m (mass of the iron part to be melted) = 2 kg; t0 (initial temperature of the iron part) = 39 ºС.
Constants: tmelt (temperature at which melting begins) = 1539 ºС; C (specific heat of iron) = 460 J / (kg * K); λ (specific heat of fusion of iron) = 2.7 * 10 ^ 5 J / kg.
The amount of heat that will need to be spent: Q = Q1 + Q2 = C * m * (tpl – t0) + λ * m = (C * (tpl – t0) + λ) * m.
Calculation: Q = (460 * (1539 – 39) + 2.7 * 10 ^ 5) * 2 = 1 920 000 J (1.92 MJ).