How much heat must be given to 2 kg of ice whose temperature is 0 degrees Celsius

How much heat must be given to 2 kg of ice whose temperature is 0 degrees Celsius so that it melts and the resulting water heats up to 50 degrees

m = 2 kg.
t1 = 0 ° C.
t2 = 50 ° C.
C = 4200 J / kg * ° С.
λ = 3.4 * 10 ^ 5 J / kg.
Q -?
Q = λ * m + C * m * (t2 – t1).
Q = 3.4 * 10 ^ 5 J / kg * 2 kg + 4200 J / kg * ° C * 2 kg * (50 ° C – 0 ° C) = 11 * 10 ^ 5 J.
Answer: for melting ice and heating water, thermal energy is needed Q = 11 * 10 ^ 5 J.