How much heat must be imparted to ice with a mass of m = 1.5 kg at a temperature of t = -20 ° C in order to heat it up to the melting

How much heat must be imparted to ice with a mass of m = 1.5 kg at a temperature of t = -20 ° C in order to heat it up to the melting point and completely melt it? (c = 2.1 * 10 ^ 3 J / kg * ° C, specific heat of melting of ice = 3.33 * 10 ^ 5 J / kg * ° C)

Q1 = m * C (tpl-t1)
[Q] = J
Q2 = m * “lambda”
[Q] = J
Q1 = 1.5 * 2100 * (0 – (- 20)) = 63000 J
Q2 = 1.5 * 3.4 * 10 (fifth power) = 510,000 J
Q = Q1 + Q2
Q = 63,000 + 510,000 = 573,000 J
Answer: 573000 J or 573 kJ