How much heat must be spent on the evaporation of 200 g of ether taken at a temperature of 25 ° C?

t1 = 25 ° С,
m = 200g = 0.2kg,
r = 355000J / kg – specific heat of vaporization of ether,
t2 = 35 ° С – boiling point of ether,
c = 2340J / (kg * deg) – specific heat of ether;
Q -?;
It is necessary to spend heat on heating the ether to the boiling point and on its evaporation:
Q = Q1 + Q2,
where
Q1 = m * c * (t2 – t1),
Q2 = m * r;
Q = m * c * (t2 – t1) + m * r = 0.2 * 2340 * 10 + 0.2 * 355000 = 75680 J.