How much heat must be spent to convert 1 kg ice taken at a temperature of minus 10 ° C into water.

univerkov | June 23, 2021 | education

Data: m (ice mass) = 1 kg; t0 (initial temperature of taken ice) = -10 ºС.

Constants: Сl (specific heat capacity of ice) = 2100 J / (kg * K); tmelt (ice melting temperature) = 0 ºС; λ (specific heat of fusion) = 3.4 * 10 ^ 5 J / kg.

The heat expended for the transformation of 1 kg of ice into water is determined by the formula: Q = Сl * m * (tmelt – t0) + λ * m.

Let’s calculate: Q = 2100 * 1 * (0 – (-10)) + 3.4 * 10 ^ 5 * 1 = 361 * 10 ^ 3 J (361 kJ).

Answer: To convert 1 kg of ice into water, 361 kJ of heat was spent.

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