How much heat must be spent to heat 125 g of ice with a temperature of -10 degrees C to a temperature of 50 degrees C?

univerkov | September 7, 2021 | education

Given: m (mass of ice taken) = 125 g (0.125 kg); t0 (ice temperature before heating) = -10 ºС; t (temperature of the obtained water) = 50 ºС.

Reference values: Cl (specific heat capacity of ice) = 2100 J / (kg * ºС); λ (beats heat of melting of ice) = 3.4 * 10 ^ 5 J / kg; Sv (specific heat capacity of water) = 4200 J / (kg * ºС).

The amount of heat expended for the process: Q = Cl * m * (0 – t) + λ * m + Cw * m * (t – 0) = m * (Cl * (0 – t) + λ + Cw * (t – 0)) = 0.125 * (2100 * (0 – (-10)) + 3.4 * 105 + 4200 * (50 – 0)) = 71 375 J.

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