How much heat must be spent to melt iron weighing 1 kg taken at a temperature of 10 degrees?

Initial data: m (weight of iron taken) = 1 kg; t0 (initial temperature of iron) = 10 ºС.

Reference data: C (specific heat of iron) = 460 J / (kg * K); λ (specific heat of fusion of iron) = 27 * 10 ^ 4 J / kg; tmelt (temperature at which iron begins to melt) = 1535 ºС.

The formula for calculating the required amount of heat: Q = C * m * (tpl – t0) + λ * m.

Let’s perform the calculation: Q = 460 * 1 * (1535 – 10) + 27 * 10 ^ 4 * 1 = 971500 J.

Answer: You will need to spend 971500 J of heat.