How much heat must be transferred to 10 kg water taken at the boiling point to convert it into steam?
May 31, 2021 | education
| The vaporization process is described by the formula:
Q = λ * m,
where λ is the specific heat of vaporization of the substance (we find it from the table λ = 2.3 * 10 ^ 6 J / kg), m is the mass.
Q = 10 kg * 2.3 * 10 ^ 6 J / kg = 23 * 10 ^ 6 J.
Answer: in order to convert water into steam, it needs to transfer 23 * 10 ^ 6 J of energy.
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