How much heat must be transferred to water weighing 5 kg to heat it from 20 degrees to 80 degrees?
| May 18, 2021 | education
Problem data: m (mass of water, which was supplied with heat) = 5 kg; t1 (temperature before heat transfer) = 20 ºС; t2 (final heating temperature) = 80 ºС.
Constants: С (specific heat capacity of water) = 4200 J / (kg * ºС).
The amount of heat that will need to be transferred to water is determined by the formula: Q = C * m * (t2 – t1).
Calculation: Q = 4200 * 5 * (80 – 20) = 1260000 J (1.26 MJ).
Answer: Water needs to transfer 1.26 MJ of heat.
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