How much heat needs to be spent so that 4 kg of boiling water out of 4 kg of snow at a temperature of -10 ° C.

Given:
m = 4 kg – snow mass
t1 = -10 C – snow temperature
t2 = 0 C – snow melting temperature
t3 = 100 C – boiling water temperature
C1 = 2100 J / kg * C – specific heat capacity of snow
L = 330,000 J / kg – specific heat of melting of snow
С2 = 4200 J / kg * С – specific heat of water
Q-?
Q1 = C1 * m * (t2-t1)
Q2 = L * m
Q3 = C2 * m * (t3-t2)
Q = Q1 + Q2 + Q3
Q1 = 2100 * 4 * (0 + 10) = 84000 J
Q2 = 330,000 * 4 = 1,320,000 J
Q3 = 4200 * 4 (100-0) = 1680000 J
Q = 1680000 + 84000 + 1320000 = 3084000 J = 3084 kJ