How much heat needs to be spent to evaporate 500 g of alcohol taken at 18 degrees Celsius?

univerkov | July 3, 2021 | education

Initial data: m (mass of alcohol for evaporation) = 500 g; t0 (temperature before heating) = 18 ºС.

Constants: t (boiling point of ethanol) = 78.3 ºС; C (specific heat capacity) = 2500 J / (kg * K); L (beats heat of vaporization) = 9 * 10 ^ 5 J / kg.

SI system: m = 500 g = 0.5 kg.

Let’s compose a formula for calculating the required heat: Q = Q1 (heating) + Q2 (vaporization) = m * (C * (t – t0) + L).

Q = 0.5 * (2500 * (78.3 – 18) + 9 * 10 ^ 5) = 525 375 J.

Answer: For the evaporation of alcohol, 525,375 J of heat is needed.

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