How much heat needs to be spent to get 4 kg of boiling water from 4 kg of snow at a temperature of -10?

Given:
c (c) = 4200 J * kg / ° С
c (l) = 2100 J * kg / ° С
λ (l) = 330,000 J / kg
m (h) = 4 kg
m (l) 4 kg
t ° 0 = -10 ° С
t ° 1 = 0 ° С
t ° 2 = 100 ° С
Find: Q =?
Decision:
To find the required amount of heat, add up the amount of heat needed to heat ice, to melt ice, and to heat water
Q = Q (n.a.) + Q (t.l.) + Q (n.a.)
Q (n.l.) = C (l) m (l) (t ° 1-t ° 0)
Q (n.l.) = 2100 * 4 * (0 ° + 10 °) = 84000 J
Q (tl) = λ (l) m (l)
Q (tl.) = 330,000 * 4 = 1,320,000 J
Q (n.v.) = C (in) m (in) (t ° 2-t ° 1)
Q (n.v.) = 4200 * 4 * (100 ° -0 °) = 1680000 J
Q = 84000 + 1320000 + 1680000 = 3084000 J
Answer: Q = 3084000 J.