How much heat needs to be spent to melt 100 g of ice at 0 ° C? 100 g of ice at -20 ° C?

m = 100 g = 0.1 kg.

t1 = 0 ° C.

t2 = – 20 ° C.

C = 2100 J / kg * ° C.

λ = 330 * 10 ^ 3 J / kg.

Q1 -?

Q2 -?

The amount of heat Q1 required to melt ice at the melting temperature is determined by the formula: Q1 = λ * m, where λ is the specific heat of melting, m is the mass of ice.

Q1 = 330 * 10 ^ 3 J / kg * 0.1 kg = 33 * 10 ^ 3 J.

The amount of heat Q2 required for melting ice taken at a temperature of t2 is determined by the formula: Q2 = C * m * (t1 – t2) + λ * m, where C is the specific heat capacity of ice, t2 is the initial ice temperature, t1 is the melting point of ice.

Q2 = 2100 J / kg * ° C * 0.1 kg * (0 ° C – (- 20 ° C) + 330 * 10 ^ 3 J / kg * 0.1 kg = 37200 J.

Answer: Q1 = 33 * 10 ^ 3 J, Q2 = 37200 J.



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