How much heat was used to heat the iron box and melt the tin if their initial temperature was 32 ° t?

How much heat was used to heat the iron box and melt the tin if their initial temperature was 32 ° t? The weight of the box is 300 g, and the weight of tin is 100 g.

Given: t0 = 32 ºС; m1 (box) = 300 g (0.3 kg); m2 (tin) = 100 g (0.1 kg).

Constants: tmelt (temperature of tin melting) ≈ 232 ºС; C1 (iron) = 460 J / (kg * ºС); C2 (tin) = 230 J / (kg * ºС); λ (beats heat of fusion) = 59 * 103 J / kg.

1) Heating the box: Q1 = C1 * m1 * (tmelt – t0) = 460 * 0.3 * (232 – 32) = 27600 J.

2) Heating of tin: Q2 = C2 * m2 * (tmelt – t0) = 230 * 0.1 * (232 – 32) = 4600 J.

3) Melting of tin: Q3 = L * m = 59 * 103 * 0.1 = 5900 J.

4) Q = 27600 + 4600 + 5900 = 38100 J (38.1 kJ).