How much heat will a lead tile weighing 1 kg release when it cools down by 7 ° C?

Initial data: m (weight of the lead tile) = 1 kg; Δt (change in tile temperature during cooling) = 7 ºС.

Reference values: Cc (specific heat of lead) = 140 J / (kg * K).

The amount of heat that the lead plate will release during cooling is determined by the formula: Q = Cc * m * Δt.

Calculation: Q = 140 * 1 * 7 = 980 J.

Answer: When cooled, the lead plate will release 980 J of heat.

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