How much heat will a lead tile weighing 1 kg release when it cools down by 7 ° C?
| September 26, 2021 | education
Initial data: m (weight of the lead tile) = 1 kg; Δt (change in tile temperature during cooling) = 7 ºС.
Reference values: Cc (specific heat of lead) = 140 J / (kg * K).
The amount of heat that the lead plate will release during cooling is determined by the formula: Q = Cc * m * Δt.
Calculation: Q = 140 * 1 * 7 = 980 J.
Answer: When cooled, the lead plate will release 980 J of heat.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
