How much heat will be released during the complete combustion of 0.05 m3 alcohol?

Q = q * m is the combustion formula, q is the specific combustion, given in the tables. P (density) = m / v -> m = P * v = 0.7905 The density of ethyl alcohol is 0.7905 g / cm ^ 3. I will convert from g / cm ^ 3 to g / m ^ 3, but you give me the volume in m.m = 790500 * 0.05 = 39525 g = 39.525 kg In the table we find the specific combustion for alcohol, 2.7 * 10 ^ 7 J / kg. Q = 2.7 * 10 ^ 7 * 39.525 = 1067175000 J = 1067175 kJ