V = 5 liters = 0.005 m ^ 3 – the volume of gasoline;
ro = 710 kg / m ^ 3 is the density of gasoline;
q = 44 * 10 ^ 6 J / kg – specific heat of combustion of gasoline.
It is required to determine Q (Joule) – the amount of heat that will be released during the complete combustion of gasoline.
Q = q * m = q * V * ro = 44 * 10 ^ 6 * 710 * 0.005 = 156.2 * 10 ^ 6 Joules.
Answer: with the complete combustion of gasoline, an energy equal to 156.2 * 10 ^ 6 Joules will be released.
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