Data: V (volume of consumed alcohol) = 0.9 m3; ρ (density of alcohol) = 800 kg / m3; qc – beats. the heat of combustion of alcohol (qc = 27 MJ / kg).
The released heat: Q = ρ * V * qс = 0.9 * 800 * 27 = 19440 MJ = 19.44 GJ.
Answer: When burning alcohol with a volume of 0.9 m3, 19.44 GJ of heat will be released.
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