How much heat will be released during the complete combustion of kerosene weighing 25 kg?

univerkov | December 26, 2020 | education

the specific heat of combustion of kerosene is 40.8 MJ / kg or 40.8 * 10 ^ 6 J / kg, the mass of kerosene is 25 kg, then we use the formula:
Q = qm. Q = 40.8 * 10 ^ 6 J / kg * 25 kg = 1020 (MJ) = 1.02 (GJ) * (* – “giga” – 10 ^ 9)
Answer: Q = 1.02 GJ

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