Problem data: m (initial mass of water vapor) = 2.5 kg.
Reference values: L (specific heat of condensation of water vapor) = 23 * 10 ^ 5 J / kg.
The amount of heat that will be released during the condensation of 2.5 kg of water vapor is calculated by the formula: Q = L * m.
Let’s make the calculation: Q = 23 * 10 ^ 5 * 2.5 = 57.5 * 10 ^ 5 J (5.75 MJ).
Answer: When condensation of water vapor with a mass of 2.5 kg, 5.75 MJ of heat is released.
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