How much heat will be released during the condensation of 200 g of water vapor?

How much heat will be released during the condensation of 200 g of water vapor? The specific heat of vaporization of water is 2.3 ∙ 10 ^ 6.

Given:

m = 200 grams is the mass of water vapor;

q = 2.3 * 10 ^ 6 Joule / kilogram = 2,300,000 Joule / kilogram is the specific heat of vaporization of water.

It is required to determine Q (Joule) – how much heat will be released during the condensation of water vapor of mass m.

Let’s convert mass units from grams to kilograms:

m = 200 grams = 200 * 10 ^ -3 = 0.2 kilograms.

Then the amount of heat will be equal to:

Q = q * m = 2,300,000 * 0.2 = 460,000 Joules (0.46 MJ).

Answer: when 200 grams of water vapor condenses, a heat equal to 460,000 Joules will be released.