How much heat will be released during the crystallization of 200 g of water at a temperature of 0 degrees?

Since the water is at the crystallization temperature (0 ºС), the water will no longer be cooled and only the crystallization process will take place.

Q = λ * m, where λ is the specific heat of melting (crystallization) of ice, water (λ = 34 * 10 ^ 4 J / kg), m is the mass of water (m = 200 g = 0.2 kg).

Let’s calculate the released heat:
Q = λ * m = 34 * 10 ^ 4 * 0.2 = 6.8 * 10 ^ 4 J = 68 kJ.

Answer: When 200 g of water crystallizes, 68 kJ of heat will be released.



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