How much heat will be released in 40 minutes in copper wires with a cross section of 1.5 mm2 and a length of 3 m
| December 7, 2020 | education
How much heat will be released in 40 minutes in copper wires with a cross section of 1.5 mm2 and a length of 3 m, supplying electric current to the tile, if the current is 5A.
Find the copper resistance:
R = pl / S, where p is the resistivity of copper (table)
R = 0.017 * 3 / 1.5 Ohm = 0.034 Ohm
According to the Joule-Lenz law
Q = I ^ 2 * R * t (t time in seconds)
Q = 25 * 0.034 * 40 * 60 J = 2040 J
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