How much heat will be released in a 25 Ohm resistor when a current of 1.2 A flows through it in 1.5 minutes?

According to the Joule-Lenz law, the amount of heat that is released on the resistor can be calculated using the formula:
Q = I ^ 2 * R * t, where I is the current strength (I = 1.2 A), R is the resistance of the resistor (R = 25 Ohm), t is the current flow time (t = 1.5 min = 1, 5 * 60 s = 90 s)
Let’s calculate the amount of heat:
Q = I ^ 2 * R * t = 1.2 ^ 2 * 25 * 90 = 3420 J = 3.42 kJ.
Answer. Heat will be released on the resistor in the amount of 3.42 kJ.