How much heat will be released to heat up to 100 degrees Celsius an aluminum tank with a capacity of 10 liters

How much heat will be released to heat up to 100 degrees Celsius an aluminum tank with a capacity of 10 liters, filled with water taken at a temperature of 20 degrees Celsius.

Vv = 10 l = 10 * 10 ^ -3 m ^ 3.

ρw = 1000 kg / m ^ 3.

t1 = 20 ° C.

t2 = 100 ° C.

mb = 1 kg.

Cw = 4200 J / kg * ° C.

Ca = 920 J / kg * ° C.

Q -?

The amount of heat will be the sum: Q = Q1 + Q2, where Q1 is the amount of heat required to heat the water, Q2 is the amount of heat required to heat the tank.

Q1 = Sv * mv * (t2 – t1).

We express the mass of water mw by the formula: mw = Vw * ρw.

Q1 = Sv * Vw * ρw * (t2 – t1).

Q2 = Ca * mb * (t2 – t1).

Q = Sv * Vw * ρw * (t2 – t1) + Ca * mb * (t2 – t1) = (Sv * Vw * ρw * + Ca * mb) * (t2 – t1).

= (4200 J / kg * ° C * 10 * 10 ^ -3 m ^ 3 * 1000 kg / m ^ 3 + 920 J / kg * ° C * 1 kg) (100 ° C – 20 ° C) = 3433600 J …

Answer: you need Q = 3433600 J of thermal energy.