How much heat will be released when 1 gram of gold is cooled from 150 degrees to 50 degrees?

The amount of heat released when cooling gold:
Q = C * m * (tн – tк), where С is the specific heat of gold (С = 130 J / (kg * K)), m is the mass of gold (m = 1 g = 1 * 10-³ kg), tн – initial temperature of gold (tн = 150 ºС), tк – final temperature of gold (tк = 50 ºС).
Let’s calculate the released amount of heat:
Q = C * m * (tн – tк) = 130 * 1 * 10-³ * (150 – 50) = 13 J.
Answer: When gold is cooled, 13 J of heat will be released.



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