How much heat will be released when 5 kg of water is cooled from a temperature of 10 degrees to a temperature

univerkov | January 12, 2021 | education

How much heat will be released when 5 kg of water is cooled from a temperature of 10 degrees to a temperature of 0 degrees and its further transformation into ice.

Data: m (mass of water) = 5 kg; t1 (temperature at which the water was located) = 10 ºС; t2 (temperature to which the water was cooled) = 0 ºС.
Constants: C (specific heat) = 4200 J / (kg * K); λ (specific heat of crystallization) = 34 * 10 ^ 4 J / kg.
The amount of heat that will be released for a given heat process: Q = C * m * (t1 – t2) + λ * m = (C * (t1 – t2) + λ) * m.
Calculation: Q = (4200 * (10 – 0) + 34 * 10 ^ 4) * 5 = 1,910,000 J (1.91 MJ).
Answer: Heat will be released in the amount of 1.91 MJ.

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