How much heat will be released when 500 g of centigrade water turns into ice at a temperature of 0 degrees?

So, first, let’s write down what is given to us.

Weight – 0.5 kg.

Temperature 1 = 100 C.

Temperature 2 = 0 C.

c = 4200 J / kg * C.

l = 3.4 * 10 ^ 5J / kg.

Now let’s write out the formula, from which we will build our solution.

Q = Q1 + Q2.

Next, we substitute the data.

c * m * (t1 – t2) + l * m.

Well, now we substitute the numbers into the solution.

4200 * 0.5 * 100 + 3.4 * 0.5 * 10 ^ 5

We solve the problem.

2.1 * 10 ^ 5 + 1.7 * 10 ^ 5 = 3.8 * 10 ^ 5

All values are measured in Joules in our case.

And now we write out the answer.

Answer: 3.8 * 10 ^ 5